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Old 05-31-2008, 06:42 PM
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The Homework Thread #6 ~ Need a Little Help? Ask Here.




Please post all homework-related questions on this thread.

This thread is for getting help when get stuck with researching for an essay, solving a math problem, finding the capital of a country...etc. Basically, the thread is for questions where you are only looking for the right answer or a few responses at the most. If you are looking for a wide variety of input, such as getting as many responses as possible for a survey or asking for general ideas for starting a project, you are welcome to start a new thread on it.


From the previous thread:

Quote:
Originally Posted by SilviahPaulian (View Post)
Anyone willing to translate that for me?

Guess it's French.Sorry. I'm Brazilian and i have no clue.
http://www.desafionacional.com.br/dn...526d58juyh.mp3
...
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Old 06-01-2008, 09:52 PM
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Lemurian, thanks so much for answering my question on the previous thread!
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Old 06-02-2008, 01:00 AM
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SilviahPaulian : Yes, it is french :

"le petit déjeuner" = breakfast

"fenêtre" = window

"clé" = key

This is the translation
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Old 06-02-2008, 10:51 PM
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OMG thanks so much for this thread
wait until september, i'm gonna ambush you with my french homework LOL
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Old 06-02-2008, 11:55 PM
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OMG thanks so much for this thread
wait until september, i'm gonna ambush you with my french homework LOL
I'll be happy to be ambushed with your french homework
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Old 06-08-2008, 08:31 PM
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LOL!!! French is pretty hard!
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Old 06-09-2008, 12:15 AM
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LOL!!! French is pretty hard!
I agree with you That's why I'll be here to help if someone needs me
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Old 06-10-2008, 11:16 AM
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Anyone from Britain who can tell me what it means to be British for young people today? This is for a oral exam, so please hurry!
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Old 06-15-2008, 08:10 AM
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Is there anyone good in math? i have an exam tomorrow, and I'd call one of my friends but they don't get this exercise either

There are two machines, Machine X and Machine Y, and they both produce Keys. Machine X produces 60% of the keys and Machine Y produces 40%
2% of all the key's produces by Machine X can't be used and
0,9% of all the key's produced by Machine Y can't be used.

At the and of the day, the boss picks 5 keys randomly

- What's the chance they can all be used
- What's the chance only one of them can be used
- What's the chance one or more can be used

Please? I'd be grateful for the rest of my life because I can't fail this exam.
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Old 06-15-2008, 08:26 AM
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I have to do some hw soon.
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Old 06-15-2008, 01:10 PM
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Quote:
Originally Posted by Caroo (View Post)
Is there anyone good in math? i have an exam tomorrow, and I'd call one of my friends but they don't get this exercise either

There are two machines, Machine X and Machine Y, and they both produce Keys. Machine X produces 60% of the keys and Machine Y produces 40%
2% of all the key's produces by Machine X can't be used and
0,9% of all the key's produced by Machine Y can't be used.

At the and of the day, the boss picks 5 keys randomly

- What's the chance they can all be used
- What's the chance only one of them can be used
- What's the chance one or more can be used

Please? I'd be grateful for the rest of my life because I can't fail this exam.
ok well if i've done my math correctly there's a 99.98% chance that they can all be used although I wouldn't quote me on that This is reallycomplicated and I think I might be doing something wrong. I can't figure it out. what Math course is this? I'll ask my step mom if she's here, She's a math major.
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Old 06-15-2008, 01:58 PM
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Quote:
Originally Posted by mcgoslinginlove (View Post)
ok well if i've done my math correctly there's a 99.98% chance that they can all be used although I wouldn't quote me on that This is reallycomplicated and I think I might be doing something wrong. I can't figure it out. what Math course is this? I'll ask my step mom if she's here, She's a math major.
Well, I finally understand it after a lot of hours and some help from a friend, so this is how it's done

- 2% of 60% is (2/100)x(60/100)=120/10000=1,2%
- 0,9% of 40% is (0,9/100)x(40/100)=36/10000=0,36%
so in total the (1,2%+0,36%)=1,56% of the keys can't be used.

- What's the chance they can all be used?
The joint probability of a series of events is P=P(E1) x P(E2)...x P(En)
In this case on 5 events the probability is (100% - 1,56%) x (100% - 1,56%) x (100% - 1,56%) x (100% - 1,56%) x (100% - 1,56%) = 92,44%

- What's the chance only one of them can be used?
It's the joint probability of "one can be used" and "4 can't be used" so:
(100% - 1,56%) x 1,56% x 1,56% x 1,56% x 1,56% => (5,83 e-8 )^5

- What's the chance one or more can be used?
It's 100% -the chanche that all of them can't be used so:
100%- [(1,56%)x(1,56%)x(1,56%)x(1,56%)x(1,56%)]=100% - 9,239e-10= almost 1...



Thank you anyway
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Old 06-15-2008, 02:10 PM
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ha ok see me and my friend were doing it way different but i get it. Thank god i dont have to take math anymore.
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Old 06-16-2008, 07:08 AM
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i have it 6 hours a week and unfortunately no choice to drop it
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Old 06-24-2008, 01:28 PM
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i have it 6 hours a week and unfortunately no choice to drop it
I have Calculus next year...and I'm not looking forward to it.
Not a fan of math.
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